Question

How do you find the period of `y = 5 sin(4x−2)−3`?

Answer 1

I found: `"period"=pi/2` radians.

Explanation:

The period of your `sin` function can be found observing the number multiplying the `x` in the argument: in this case the argument of the `sin` is: `(4x-2)` so that the important number will be `4`.
It is important because it is connected to the period `T` as:
`4=(2pi)/T`
rearranging you get that:
`T=(2pi)/4=pi/2` meaning that your curve will repeat itself every `pi/2` radians:
Graphically you can see this as:
graph{5sin(4x-2)-3 [-20.28, 20.26, -10.14, 10.14]}
Try using the `x` positions two consecutive peaks and see if their spacing is `pi/2`.