Question

Question #7e002

Answer 1

`color(red)(2)NaCl + H_2SO_4 = Na_2SO_4+color(red)(2)HCl`

Explanation:

Since we have `Na_color(red)(2)SO_4` on the right side
the left side must have a multiple of `color(red)(2)` `NaCl`'s

Trying the minimum of `color(red)(2)NaCl` on the left implies we will need to have a multiple of `color(red)(2)color(white)(" ")Cl`'s in `HCl` on the right;

but the `H_color(red)(2)` in the `H_2SO_4` on the left provides the `color(red)(2) H`'s needed for `color(red)(2)HCl` to work out.