Question

How do you solve for x in `6.428 = 1.263 ^ (x)`?

Answer 1

I found: `x=7.9689`

Explanation:

Take the natural log of both sides:

`color(red)(ln)6.428=color(red)(ln)1.263^x`

use the property of logs on the exponent of the argument:

`color(red)(ln)6.428=color(blue)(x)color(red)(ln)1.263`

rearrange:

`x=(ln(6.428))/(ln(1.263))=7.9689`