Question

How do you factor completely `x^2 - 6x + 8`?

Answer 1

For `x^2-6x+8=0`
`0=x^2-4x-2x+8`
`0=x(x-4)-2(x-4)`
`0=(x-4)(x-2)`

`(x-4)=0` OR `(x-2)=0`
`x=4` OR `x=2`

For `x=4 and 2`
`x^2-6x+8` is zero
Hence `4 and 2` are its factors