Question

How do you expand `ln(x^2/y^2)`?

Answer 1

`2lnx-2lny`

Explanation:

The first law of logs you will want to use is `ln(a/b)=lna-lnb`, so

`ln(x^2/y^2)=lnx^2-lny^2`

Another law of logs is that an exponent inside the log is the same as a coefficient outside, or `lnc^2=2lnc`, so

`lnx^2-lny^2=2lnx-2lny`