How do you solve #-1/2x+12=23#?

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Answer 1 · 2016-05-01T08:27:47

#x = -22#

#-1/2x + 12 = 23#

First, subtract 12 from both sides of the equation. This results in:

#-1/2x = 11#

Then multiply both sides of the equation by #-2# so that the #x# is all that remains on the left side of the equation:

#-2(-1/2x) = 11(-2)#

Therefore,

#x = -22#