Question

How do you solve `2 ln x = 1`?

Answer 1

`x=sqrt(e)`

Explanation:

`2 ln(x) = 1`
`ln(x^2) = 1`
`x^2 = e^1`
`x = +-sqrt(e)`

Since `ln(x)` is not defined for `x<0`
`x = sqrt(e)`