Question

How do you evaluate `log_4 16 =x`?

Answer 1

`log_4(16) = 2`

Explanation:

We will use the following:

• `log_a(a) = 1`
• `log(a^x) = xlog(a)`

with those, we have

`log_4(16) = log_4(4^2)`

`=2log_4(4)`

`=2(1)`

`=2`