Question

An excess of hydrogen reacts with 14.0 g of `N_2`. What volume of ammonia will be produced at STP?

Answer 1

`V=33.6L`

Explanation:

The reaction between hydrogen and nitrogen is the following:

`3H_2(g)+N_2(g)->2NH_3(g)`

Using the mass of nitrogen `m=14.0g`, we can first find the number of mole of ammonia that will be produced:

`?molNH_3=14.0cancel(gN_2)xx(1cancel(molN_2))/(28.0cancel(gN_2))xx(3molNH_3)/(1cancel(molN_2))=1.50molNH_3`

It is known that at STP, one mole of gas occupies a volume of `22.4L`. This is called the molar volume.

Thus, the ammonia produced will occupy the following volume:

`?L=1.50cancel(molNH_3)xx(22.4L)/(1cancel(molNH_3))=33.6 L`