Question

Question #605aa

Answer 1

`V_2=9.06mL`

Explanation:

Since the number of mole `n` is constant and the factors changing are the volume, the pressure and temperature; we can modify the ideal gas law `PV=nRT` to be:

`(PV)/T=k` where `k=nR` is constant.

Therefore, `(P_1V_1)/(T_1)=(P_2V_2)/(T_2)`

`=>V_2=(P_1V_1)/(T_1)xx(T_2)/(P_2)=(0.975cancel(atm)xx8.88mL)/(261cancel(K))xx(273cancel(K))/(1cancel(atm))=9.06mL`

Therefore, the volume of the gas at STP would be `V_2=9.06mL`.