What is #(8x^4y^2)/(3z^3) * (9xy^2z^6)/(4y^4)#?

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Answer 1 · 2016-05-06T15:39:04

#6x^5z^3#

#(8x^4y^2)/(3z^3) * (9xy^2z^6)/(4y^4)#

Multiply like terms, add exponents of like terms.

# = (72x^5y^4z^6)/(12z^3y^4)#

#=(6cancel(72)x^5cancel(y^4)z^6)/(cancel(12)z^3cancel(y^4))#

#=(6x^5z^6)/z^3#

Subtract exponents when dividing like terms.

#=6x^5z^3#