How do you solve #5x^2 = 125#?

Question

11138 views around the world

You can reuse this answer
Creative Commons License

Answer 1 · 2016-05-06T21:03:27

x=5

5#x^2#= 125

Firstly divide by five which gives:

#x^2#=25

Then square root #x^2# to have x alone

x=√25=5

x=5

Answer 2 · 2016-05-06T21:04:25

#x=±5#

#5x^2=125#

#cancel(5)x^2=cancel(125)#

#x^2=25#

#sqrt(x^2)=sqrt (5^2)#

#x=±5#