How do you divide #(5m^3 - 7m^2 + 14) / (m^2 - 2)#? Algebra Rational Equations and Functions Division of Polynomials 1 Answer P dilip_k May 7, 2016 #Here , quotient" =>(5m- 7) ##"and Remainder" =10m# Explanation: #(5m^3 - 7m^2 + 14) / (m^2 - 2)# #=>((5m(m^2-2)+10m - 7(m^2-2)-cancel14 +cancel 14) )/ (m^2 - 2)# #=>((5m(m^2-2) - 7(m^2-2)+10m) )/ (m^2 - 2)# #=>((5m(m^2-2))/ (m^2 - 2)- 7(m^2-2)/ (m^2 - 2)+(10m)/(m^2 - 2) )# #=>(5m- 7+(10m)/(m^2 - 2) )# Answer link Related questions What is an example of long division of polynomials? How do you do long division of polynomials with remainders? How do you divide #9x^2-16# by #3x+4#? How do you divide #\frac{x^2+2x-5}{x}#? How do you divide #\frac{x^2+3x+6}{x+1}#? How do you divide #\frac{x^4-2x}{8x+24}#? How do you divide: #(4x^2-10x-24)# divide by (2x+3)? How do you divide: #5a^2+6a-9# into #25a^4#? How do you simplify #(3m^22 + 27 mn - 12)/(3m)#? How do you simplify #(25-a^2) / (a^2 +a -30)#? See all questions in Division of Polynomials Impact of this question 1470 views around the world You can reuse this answer Creative Commons License