Question

A charge of `5 C` passes through a circuit every `2 s`. If the circuit can generate `25 W` of power, what is the circuit's resistance?

Answer 1

`=4Omega`

Explanation:

We know
`"Current"(I)=("Charge passed"(q))/("Time"(t))=5/2A=2.5A`
Again
`Power(P)=I^2xxR`
Therefore Resistance `R =P/I^2=25/2.5^2=4Omega`