How do you simplify $log_4 8$ ?

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Answer 1 · 2016-05-07T16:10:59

Use the logarithmic properties:

$log_a(b^c)=c*log_a(b)$

$log_a(b)=log_c(b)/log_c(a)$

You can notice that $c=2$ fits this case since $8$ can be derived as a power of $2$ . Answer is:

$log_(4)8=1.5$

$log_(4)8$

$log_(2)8/log_(2)4$

$log_(2)2^3/log_(2)2^2$

$(3*log_(2)2)/(2*log_(2)2)$

$3/2$

$1.5$

How do you simplify log_4 8log_4 8?