Question

What is the derivative of `(x^3-3x^2+4)/x^2`?

Answer 1

`1-8/x^3`

Explanation:

Divide each term on the numerator by `x^2`

`(x^3)/x^2-(3x^2)/x^2+4/x^2=x-3+4x^-2`

now differentiating using the `color(blue)" power rule "`

`rArrd/dx(x-3+4x^-2)=1-8x^-3=1-8/x^3`