What is the 24th term of an arithmetic sequence where a1=8 and a9= 56?

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Answer 1 · 2016-05-09T13:56:27

#56= 8 + (9 - 1)d#

#48 = 8d#

#6 = d#

The common difference is of #6#. We can now find the 24th term using the formula #t_n = a + (n - 1)d#

#t_24 = 8 + (24 - 1)6#

#t_24 = 146#

Thus, the 24th term is #146#.

Hopefully this helps!