How do you factor #-62x^5 y^2 + 124x^4 y^3#?
1 Answer
May 9, 2016
Explanation:
Both terms are divisible by
#-62x^5y^2+124x^4y^3=62x^4y^2(-x+2y) = 62x^4y^2(2y-x)#
Both terms are divisible by
#-62x^5y^2+124x^4y^3=62x^4y^2(-x+2y) = 62x^4y^2(2y-x)#