How do you factor completely #xy+2x+4y+8#?
1 Answer
May 9, 2016
Explanation:
Factor by grouping:
#xy+2x+4y+8#
#=(xy+2x)+(4y+8)#
#=x(y+2)+4(y+2)#
#=(x+4)(y+2)#
Factor by grouping:
#xy+2x+4y+8#
#=(xy+2x)+(4y+8)#
#=x(y+2)+4(y+2)#
#=(x+4)(y+2)#