#"first; let's find the total capacitances in circuit. "#
#"for capacitors "4 mu F and 2 mu F," total="4+2=6 mu F"(in parallel)"#
#"for capacitors "6 mu F " and " 6 mu F" " 1/("total")=1/(6)+1/6#
#"total capacitance="6/2=3 mu F#
#C=3*10^-6F" (total capacitance for circuit")#
#C=Q/V#
#Q=C*V#
#Q=3*10^-6*12#
#Q=36*10^-6C" (total charge for circuit)"#
#x+2x=36*10^-6#
#3x=36*10^-6#
#x=12.10^-6C#
#"charge of 2"mu F rarr 12*10^-6C#
#"charge of 4"mu F rarr 24*10^-6C#
#"charge of 6"mu F rarr 36*10^-6C#
#"charge of circuit" rarr 36*10^-6C#