How do you differentiate #y= (sqrt(x)+x) / x^2#?
1 Answer
May 10, 2016
Explanation:
divide terms on numerator by
#x^2#
#rArry=x^(1/2)/x^2+x/x^2=x^(-3/2)+x^-1# now differentiate each term using the
#color(blue)" power rule "#
#dy/dx=-3/2 x^(-5/2)-1x^-2# and writing with positive indices gives.
#dy/dx=-(3/(2x^(5/2))+1/x^2)#