If a projectile is shot at an angle of (pi)/8 and at a velocity of 32 m/s, when will it reach its maximum height?

1 Answer
May 10, 2016

t=1.24 "sec"

Explanation:

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"the vertical component of velocity is zero,if Object reaches its maximum height"

v_y=v_i*sin alpha-g*t

0=32*sin(pi/8)-9.81*t

0=32*0.38-9.81*t

0=12.16-9.81*t

9.81*t=12.16

t=(12.16)/(9.81)

t=1.24 "sec"