How would you simplify #(3 sqrt(5)) div sqrt(7)#?

1 Answer
May 10, 2016

#(3sqrt(35))/7#

Explanation:

Mathematical convention is to try and 'get rid' of any roots (radicals) that are in the denominator.

Write as:#" "(3sqrt(5))/sqrt(7)#

Multiply by 1 but in the form of #1=sqrt(7)/(sqrt(7))#

#(3sqrt(5))/sqrt(7)xxsqrt(7)/sqrt(7)" "=" "(3sqrt(5)xxsqrt(7))/7#

#(3sqrt(5xx7))/7" "=" "(3sqrt(35))/7#