A container with a volume of #6 L# contains a gas with a temperature of #240^o K#. If the temperature of the gas changes to #330 ^o K# without any change in pressure, what must the container's new volume be?

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Answer 1 · 2016-05-10T11:55:38

#V_f=8.25 L#

#"initial volume: "V_i=6L#
#"initial temperature: "T_i=240 ^o K#

#"final temperature: "T_f=330^o K#
#"final volume :"V_f=?#

#V_i/T_i=V_f/T_f#

#6/240=V_f/330#

#V_f=(330*6)/240#

#V_f=8.25 L#