Question

A `2500*m^3` volume of gas under `200*kPa` pressure is compressed to `500*kPa`. What is the new volume?

Answer 1

Given constant temperature, we use Boyle's law, `Pprop1/V`

Explanation:

So `P_1V_1=P_2V_2`, and thus,

`V_2` `=` `(P_1V_1)/P_2` `=` `(200*kPaxx2500*m^3)/(500*kPa)` `=` `??*m^3`