How do you solve #x - 2y = 10# and #1/2x - 2y = 4# using substitution?
1 Answer
May 11, 2016
Explanation:
Given
[1]
[2]
We can rearrange [1] to give us an equation in terms of just
[3]
This allows us to substitute
[4]
Simplifying
[5]
[6]
[7]
Now we can substitute
[8]
Simplifying
[9]