Question

How do you convert `r=6sin(theta)` to rectangular form?

Answer 1

`x=6*cos(theta)sin(theta), y = 6*sin(theta)^2`

Explanation:

The pass equations are: `x=r *cos(theta),y=r *sin(theta)` then substituting we get `x=6*cos(theta)*sin(theta), y = 6*sin(theta)^2`