Question

How do you solve `log_5x^10 - log_5x^2 = 21`?

Answer 1

Use the log rule `log_an - log_am = log_a(n/m)`.

Explanation:

`log_5(x^10/x^2) = 21`

`x^8 = 5^21`

`x = +-root(8)(5^21)`

`x = +-68.359`

Hopefully this helps!