What volume of 1.0 M #CuSO_4# would you need to make .750 L of a .20 M solution?

1 Answer
anor277
May 13, 2016

#0.150*L# are required.

Explanation:

#"Concentration"# #=# #"Moles of solute"/"Volume of solution"#.

And thus #"Moles of solute "(n)# #=# #"Concentration "(mol*L^-1)xx"volume "(L)#

In the required volume there are #0.750*Lxx0.20*mol*L^-1# #=# #0.150*mol#.

Thus, in the starting volume, we need #0.150*L#, which contains #0.150*mol#. This volume is then diluted to #0.750*L#.

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