Question #907e5

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Answer 1 · 2016-05-13T12:27:29

#-40^o#

Note the conversion formula:

#C/5 = (F-32)/9.......(1)#

We are required to find such an #x# such that #C=x=F#. Lets try putting this on relation #(1)#:

#x/5 = (x-32)/9#

#=>9x = 5x-160#

#=>4x = -160#

#=> x = -40#

Hence, #-40^oC = -40^oF#