Question

A charge of `25 C` passes through a circuit every `2 s`. If the circuit can generate `25 W` of power, what is the circuit's resistance?

Answer 1

To find the resistance, we need to know voltage and current.

Explanation:

Current `I`:
`I=(25C)/(2s)=12.5C//s=12.5A`

Voltage `U`
can be derived from power `p` and current `I`:
`p=UxxI->U=p/I=(25W)/(12.5A)=2V`

Resistance `R`
`R=U/I=(2V)/(12.5A)=0.16Omega`