Question

How do you rationalize the denominator and simplify `sqrt8/sqrt3`?

Answer 1

`(2sqrt(6))/3`

Explanation:

Multiply by 1 but in the form of `1=sqrt(3)/(sqrt(3))`

`sqrt(8)/sqrt(3)xxsqrt(3)/sqrt(3)`

`(sqrt(8)xxsqrt(3))/3`

`sqrt(8xx3)/3`

`sqrt(2^2xx2xx3)/3`

`(2sqrt(6))/3`