Question

How do you simplify `4- sqrt( r+6) = -sqrt( r-2)`?

Answer 1

`r = 3`

Explanation:

grouping `4= sqrt[r+6]-sqrt[r-2]` and squaring both sides of the equation,
`16 = 4+2r+2sqrt((r+6)(r-2))`
Simplifying and grouping radicals to the right
`6-r=sqrt((r+6)(r-2))`
Squaring again both sides
`(6-r)²=(r+6)(r-2)`
After simplifications we get
`r = 3`