Question

Question #600a1

Answer 1

`400 Omega`. `R = R_1 + R_2` , as they are in series.

Explanation:

When resistances are connected in series, same current flows through them. Therefore, according to Ohm's law(`V=I*R`)

Let,
`V_1=`potential difference across `R_1`
`V_2=`potential difference across `R_2`

As they are in series,

`V_"total"=V_1+V_2`
So,
`I*R_"total"=I*R_1+I*R_2`

Therefore,
`R_"total"=R_1+R_2`

So, the answer here is `300+100=400 Omega`.