Question #600a1

1 Answer

400 Omega. R = R_1 + R_2 , as they are in series.

Explanation:

When resistances are connected in series, same current flows through them. Therefore, according to Ohm's law(V=I*R)

Let,
V_1=potential difference across R_1
V_2=potential difference across R_2

As they are in series,

V_"total"=V_1+V_2
So,
I*R_"total"=I*R_1+I*R_2

Therefore,
R_"total"=R_1+R_2

So, the answer here is 300+100=400 Omega.