Question

How do you find the midpoint of (-1,0) and (2,3)?

Answer 1

`(x,y)_("mid point")=(3/2,3/2)`

Explanation:

The mid point is the mean of the change in x and the mean of the change in y

`(x,y)_("mid point") = ((x_2-x_1)/2,(y_2-y_1)/2)`

`(x,y)_("mid point") = ((2-(-1))/2,(3-0)/2)=(3/2,3/2)`