What is the period of #f(t)=cos ( ( 7 t ) / 2 ) #?

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Answer 1 · 2016-05-16T06:52:51

#(4pi)/7#.

The period for both sin kt and cos kt is (2pi)/k.

Here, k = = #7/2#. So, the period is #4pi)/7.#.

See below how it works

#cos ((7/2)(t+(4pi)/7))=cos((7t)/2+2pi)=cos((7t)/2)#

Answer 2 · 2016-05-16T07:53:52

#T=(4pi)/7#

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#y=A*cos(omega*t+phi)" general equation"#

#"A:Amplitude"#

#omega:"Angular velocity"#

#phi="phase angle"#

#"your equation:" f(t)=cos((7t)/2)#

#A=1#

#omega=7/2#

#phi=0#

#omega=(2pi)/T" T:Period"#

#7/2=(2pi)/T#

#T=(4pi)/7#