Question

How do you evaluate `3 log_3 (9) - 4 log_3 (3)`?

Answer 1

2

Explanation:

Use `log _b a = log a/log b, n log a = log a^n and log_b b=1`.

Here, `3 log_3 9 - 4 log_3 3`

`=3(log 9/log 3)-4(1)`

`=3(log (3^2)/log 3)-4`

`=6(log 3/log 3)-4=6-4 = 2`