What is #17/18 - 3/7#?

1 Answer
May 19, 2016

I found: #65/126#

Explanation:

We first need a common denominator.
Between #18# and #7# I would use #18*7=126#.

So using #126# as new denominator I wold then rearrange the numerators to get:

#(((126/18)*17)-((126/7)*3))/126=#

and then solve:

#=(119-54)/126=65/126#