What is the number of moles in 9.63 L of H_2S gas at STP?

2 Answers
May 19, 2016

0.430 mol (rounded with significant figures)

Explanation:

Any gas, at STP, will have 22.4 L per mol. Taking this into account, using dimensional analysis:

9.63 L H_2S * (1 mol H_2S)/(22.4 L H_2S)

(9.63 L H_2S)/(22.4 L H_2S)=0.4299 mol

Which rounds to 0.430 mol, with three significant figures

May 19, 2016

P.V=n.R.T

Explanation:

Use the ideal gas equation

P.V=n.R.T

Solve for n,

n=( P*V)/(R.T)

P" is the pressure of the gas (" atm")"
V" is the volume of the gas ("L")"
T" is the Kelvin temperature ("K")"
R" is the universal gas constant ("0.0821L.\atm.mol^-1.K^-1")"

n=(1.00*atm*9.63*L) /(0.0821*L*atm*mol.^-1*K^-1*273*K

n=(1.00*cancel(atm)*9.63*cancel(L)) /(0.0821*cancel(L)* cancel(atm)*mol.^-1*cancel(K^-1)*273*cancel(K)

n=0.430* mol.