What is the equation of a line that passes through #(-8, -3)# and has a slope of #-4#?

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Answer 1 · 2016-05-19T15:29:03

#y = -4x-35#

Formula for slope is:

#m = (y_2 - y_1)/(x_2 - x_1)#

using this we have,

#-4 = (-3 - y)/(-8 - x)#

#rArr-4*(-8-x) = -3-y#

#rArr32+4x = -3-y#

by rearranging we have the equation of the line which passes through #(-8,-3)# with slope #-4#

#y = -4x-35#