Question

A gas sample has a volume of 225 mL at 122 kPa. What will its volume be at 101 kPa?

Answer 1

At constant `T`, `P_1V_1=P_2V_2`

Explanation:

Thus `V_2` `=` `(P_1V_1)/P_2` `=` `(225*mLxx122*kPa)/(101*kPa)` `=` `??mL`