Question

How do you find `abs( -3-6i )`?

Answer 1

`|-3-6i|=3sqrt5`

Explanation:

Absolute value of a complex number `a+ib` is denoted as `|a+ib|`

and is given by `sqrt(a^2+b^2)`

Hence absolute value `|-3-6i|` is

`sqrt(3^2+6^2)=sqrt(9+36)=sqrt45=3sqrt5`