What is #5(x-y)-(x-y)#?

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Answer 1 · 2016-05-25T16:38:21

# = 4 (x -y) #

#5(x−y)−(x−y)#

#=5(x−y)−1(x−y)#

# = 5 * (x) + 5 * (−y) + (−1) * (x) + (-1) *(−y)#

# = 5x -5y -x +y#

Grouping like terms:

# = 5x - x -5y +y#

# = 4x - 4y #

#4# is common to both terms:

# = 4 (x -y) #