How do you write an equation of a line going through (1,2) (-1,2)?

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Answer 1 · 2016-05-26T07:51:54

#y=2 #

#"Equation of a straight line parallel to the X-axis"#

#"First find the slope of the line passing through the two "#
#"points (1,2) and (-1,2)"#

#slope=(y_2-y_1)/(x_2-x_1)#

#slope =((2-2))/(((-1)-1))#

#slope =0 #

#y=a*x+b#

# "the point "(1,2)" is a point on the line."#

#y=0*(1)+2#

#y=2 " is the equation of a straight line parallel to the X-axis."#

graph{0*x+2 [-2.662, 2.74, -0.276, 2.423]}