How do you write an equation of a line going through (1,2) (-1,2)?

1 Answer
May 26, 2016

y=2

"Equation of a straight line parallel to the X-axis"

Explanation:

"First find the slope of the line passing through the two "
"points (1,2) and (-1,2)"

slope=(y_2-y_1)/(x_2-x_1)

slope =((2-2))/(((-1)-1))

slope =0

y=a*x+b

"the point "(1,2)" is a point on the line."

y=0*(1)+2

y=2 " is the equation of a straight line parallel to the X-axis."

graph{0*x+2 [-2.662, 2.74, -0.276, 2.423]}