A ball with a mass of #280 g# is projected vertically by a spring loaded contraption. The spring in the contraption has a spring constant of #16 (kg)/s^2# and was compressed by #3/5 m# when the ball was released. How high will the ball go?

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Answer 1 · 2016-05-26T09:18:56

#h = v^2/(2g)= (4.53557)^2/20 =1.02 (approx)#

#KE_("Ball after release") = PE _("Spring")#

#1/2mv^2 =1/2kx^2#

#mv^2 =kx^2#

#(0.28)v^2 = 16*(3/5)^2#

Solving

#v =4.53557 m/s#
#KE_("INITIAL") =PE_("FINAL")#

#1/2cancel(m)v^2 =cancelmgh#

#h = v^2/(2g)= (4.53557)^2/20 =1.02 (approx)#