Question

If 98.5 mol of an ideal gas is at 1.73 atm and 477 K, what is the volume of the gas?

Answer 1

`V=2230L`

Explanation:

Use the ideal gas law: `PV=nRT`.

The volume then could be obtained after rearranging the aforementioned expression as:

`V=(nRT)/P`

Therefore, `=>V=(98.5cancel(mol)xx0.0821(L*cancel(atm))/(cancel(K)*cancel(mol))xx477cancel(K))/(1.73cancel(atm))=2229.7L~=2230L` (rounded to 3 significant figures)