Question

If an object is moving at `150 m/s` over a surface with a kinetic friction coefficient of `u_k=2250 /g`, how far will the object continue to move?

Answer 1

`Delta x=5 m`

Explanation:

`v_i=150 m/s" initial velocity"`
`u_k=2250/g" coefficient of friction"`

`"The object is decreased by the friction force"`

`F_f=u_k*m*g"`

`F_f=2250/cancel(g)*m*cancel(g)`

`F=m*a`

`2250*cancel(m)=cancel(m)*a`

`a=2250" " m/s^2`

`v_f^2=v_i^2-2*a*Delta x`

`"the final velocity of object will be zero if object stops."`

`0=v_i^2-2*a*Delta x`

`Delta x=v_i^2/(2*a)`

`Delta x=150^2/(2250)`

`Delta x=22500/(2*2250)`

`Delta x=5 m`