How do you solve #64=2^(3x+3)#?

Question

520 views around the world

You can reuse this answer
Creative Commons License

Answer 1 · 2016-05-28T15:35:27

#x=1#

#64=2^(3x+3)=?#

#color(red)(2)^6=color(red)(2)^(3x+3)#

#"Both right and left side of equation have the same base value"#

#6=3x+3#

#6-3=3x#

#3x=3#

#x=1#