Question #28fed
1 Answer
May 29, 2016
Explanation:
You wish to find:
#int(1-2x)/(2x^2-2x+5)dx#
Let
Multiply the numerator of the integrand by
#=-1/2int(-2(1-2x))/(2x^2-2x+5)dx=-1/2int(4x-2)/(2x^2-2x+5)dx#
Substitute in
#=-1/2int(du)/u#
Note that
#=-1/2ln(2x^2-2x+5)+C#
Note that the absolute value signs are not needed because