What is the pH of a 0.0001 M solution of HNO3? pOH?

1 Answer
anor277
May 30, 2016

#pH=-log_(10)H_3O^+#;

in water #pOH=14-pH#

Explanation:

#log_10{0.0001}# #=# #log_10(10^-4)=-4#, by definition of the log function. Thus #pH# #=# #4#, and, necessarily, #pOH=10#.

Note that you should understand #log# functions. When I write #log_aB=c#, I specify that #a^c=B#; thus #log_(10)100=2,log_(10)1000=3#, and #log_(10)10^(-1)=-1#. What are #log_(10)1,000,000#, and #log_(10)10^-6#?

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